George Chartas <email@example.com> wrote:
>The decay rate is modelled by the function:
>R(t) = norm*double(exp(-tauinf*(1.d0 - exp(-t/tefold))))
>with norm = 0.00722 +/- 0.00007
> tefold = 620. +/- 66.
> tauinf = 0.582 +/- 0.024
Is the "norm" parameter in the model supposed to have an effect? The
fortran code (and the sherpa slang code) contains:
c Estimate thickness of contaminate during observation
decay = norm*exp(-tauinf*(1.0 - exp(-Tdays/tefold)))
thRho = log(decay/norm)/(MacE2 - MacE1)
That is, thRho does not depend upon norm.
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